【LeetCode】92. Reverse Linked List II 解题报告

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Subject

出处：https://leetcode.com/problems/reverse-linked-list-ii/

Reverse a linked list from position m to n. Do it in-place and in one-pass.

For example:
Given 1->2->3->4->5->NULL, m = 2 and n = 4,

return 1->4->3->2->5->NULL.

Note:
Given m, n satisfy the following condition:
1 ≤ m ≤ n ≤ length of list.

Explain

反转链表中第m 到第n 个结点

解决方案就是通过链表反转的方式，将m-n个结点反转，然后在拼接之前后之后的结点。重点就是记录第m个结点的前驱结点和第n个结点的后续结点。

链表反转的方法可参考：
http://blog.csdn.net/crazy1235/article/details/66971177

Solution

solution 1

还是通过栈的方式反转，然后拼接

    /*** 使用stack* * Runtime : 1ms* * beats 2.94% of java submissions* * @param head* @param m* @p

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【LeetCode】92. Reverse Linked List II 解题报告

Subject

Explain

Solution

solution 1

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