我有以下python脚本。我想知道是否有任何机会，它可以调整使用gpu计算能力。作用：使用秘密.令牌(32)函数，然后它将其应用于一组具有已知结果的已定义规则，如果它与所有规则匹配，则将匹配的哈希输出到一个文件中，否则将在另一个文件中写入错误的哈希。我想用gpu来做这件事，以获得更快的计算速度。谨致问候。在import random

import hashlib

import secrets

def writeFile(addString):

txtFile = open("NOTFOUND.txt", 'a')

txtFile.write(addString)

txtFile.close()

if __name__ == "__main__":

whileLoopBreak = True

txtFileRead = open("NOTFOUND.txt", 'a')

checkIfExist = 0

public_seed = 3314371705

roundList = ['1176881', '1176882', '1176883', '1176884', '1176885']

while whileLoopBreak:

tempString = secrets.token_hex(32)

txtFileRead = open("NOTFOUND.txt", 'r')

for line in txtFileRead:

while tempString == line[0:-1]:

if(tempString != line[0:-1]):

break

tempString = secrets.token_hex(32)

txtFileRead.close()

writeFile(tempString + "\n")

for i in range(0, 5):

hashString = tempString + "-" + str(public_seed) + "-" + roundList[i]

hash_object = hashlib.sha256(hashString.encode())

hex_dig = hash_object.hexdigest()

begToEnd = hex_dig[0:8]

intFromBTE = int(begToEnd, 16) % 15

if intFromBTE == 10 and roundList[i] == roundList[0]:##1

checkIfExist += 1

elif intFromBTE == 4 and roundList[i] == roundList[1]:##2

checkIfExist += 1

elif intFromBTE == 12 and roundList[i] == roundList[2]:##3

checkIfExist += 1

elif intFromBTE == 6 and roundList[i] == roundList[3]:##4

checkIfExist += 1

elif intFromBTE == 8 and roundList[i] == roundList[4]:##5

checkIfExist += 1

if checkIfExist == 5:

checkIfExist = 0

txtFile = open("serverSeedFound.txt", 'a')

txtFile.write(tempString + "\n")

print(tempString)

txtFile.close()

else:

checkIfExist = 0