xctf web之 simple

输入密码后
查看源码

<html>
<head><title>JS</title><script type="text/javascript">function dechiffre(pass_enc){var pass = "70,65,85,88,32,80,65,83,83,87,79,82,68,32,72,65,72,65";var tab  = pass_enc.split(',');var tab2 = pass.split(',');var i,j,k,l=0,m,n,o,p = "";i = 0;j = tab.length;k = j + (l) + (n=0);n = tab2.length;for(i = (o=0); i < (k = j = n); i++ ){o = tab[i-l];p += String.fromCharCode((o = tab2[i]));if(i == 5)break;}for(i = (o=0); i < (k = j = n); i++ ){o = tab[i-l];if(i > 5 && i < k-1)p += String.fromCharCode((o = tab2[i]));}p += String.fromCharCode(tab2[17]);pass = p;return pass;}String["fromCharCode"](dechiffre("\x35\x35\x2c\x35\x36\x2c\x35\x34\x2c\x37\x39\x2c\x31\x31\x35\x2c\x36\x39\x2c\x31\x31\x34\x2c\x31\x31\x36\x2c\x31\x30\x37\x2c\x34\x39\x2c\x35\x30"));h = window.prompt('Enter password');alert( dechiffre(h) );</script>
</head></html>

不断的切换输入的密码发现中间这一部分都是没有改变的
觉得可能没什么作用

重点分析

 String["fromCharCode"](dechiffre("\x35\x35\x2c\x35\x36\x2c\x35\x34\x2c\x37\x39\x2c\x31\x31\x35\x2c\x36\x39\x2c\x31\x31\x34\x2c\x31\x31\x36\x2c\x31\x30\x37\x2c\x34\x39\x2c\x35\x30"));

\x35\x35\x2c\x35这一个长串子是十六进制转义字符，其中的最后两位16进制数。
我们直接用python print 输出就能得到
数组[55,56,54,79,115,69,114,116,107,49,50]

.将得到的数字分别进行ascii处理，可得到字符串 786OsErtk12 也就是flag

a = [55,56,54,79,115,69,114,116,107,49,50]
c = ""
for i in a:b = chr(i)c = c + b
print(c)

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