//先去除" ",得到"...................................."这样的一个字符串,然后再去除一头一尾的引号

public static void replaceChar(String s){

//String s = "01290943050280128550\" \"01\" \"0\" \"13548418074\" \"923041\" \"13548418074\" \"1862      \" \"1862SMS   \" \"01\" \"0     \" \"0     \" \"0      \" \"0\" \"85 \" \"280 \" \"002801\" \"      \" \"13800280500\" \"20070129094305\" \"20070129094314\" \"PXY08 \" \"0";

String ss = s.replaceAll("\" \"","");

System.out.println(" ss ="+ss);

ss = ss.replaceAll("\"","");

System.out.println(" ss ="+ss);

}

public static void readFile(){

try{

File file = new File("D:\\dosp\\t.txt");

java.io.FileReader reader = new FileReader(file);

BufferedReader br = new BufferedReader(reader);

String s = br.readLine();

System.out.println(" s = " + s);

replaceChar(s);

}catch(Exception e){

e.printStackTrace();

}

}

public static void main(String[] args) {

Test test = new Test();

readFile();

}

以下是在文本t.txt中的例子(处于一行,每个字段用引号括住,各个字段之间有空格)

"01282356000280118304" "01" "0" "           " "923084" "13466390573" "5198      " "-GSSP     " "03" "0     " "1500  " "DB:0115" "1" "101" "    " "002801" "      " "13800280500" "20070128235602" "20070128235602" "Agent0" "0         "

进过上面函数处理后得到:

第一步得到:

"01282356000280118304010           923084134663905735198      -GSSP     030     1500  DB:01151101    002801      138002805002007012823560220070128235602Agent00         "

第二步得到:

01282356000280118304010           923084134663905735198      -GSSP     030     1500  DB:01151101    002801      138002805002007012823560220070128235602Agent00