I00030 Grades conversion

问题：将100分制的成绩转换成"优秀","良好","中等","及格"和"不及格"。

一般教科书上，实现成绩转换功能用if语句或switch语句。那是浮云。

这里用二次查表法来实现。这样做逻辑简单，程序运行速度快，语句简洁。

简单到几乎看不见逻辑语句的程序才是好程序。

程序如下：

/* I00030 Grades conversion */#include <stdio.h>int main(void)
{int score;char *result[] = {"优秀", "良好", "中等", "及格", "不及格"};int convert[] = {4, 4, 4, 4, 4, 4, 3, 2, 1, 0, 0};while(scanf("%d", &score) != EOF)if(score < 0 || score > 100)printf("分数错误!\n");elseprintf("%s\n", result[convert[score/10]]);return 0;
}

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