leetcode 6 -- ZigZag Conversion

题目

The string “PAYPALISHIRING” is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)

题意

将字符串按照锯齿形(N字形)排列，然后把从上到下把所有行按从做到右的顺序组成新的字符串
ps:其实我刚开始也把题意理解错了，wr了好几次，于是乎去学长博客取经后才理解。

    关于锯齿形解释如下：1---------------72---------6----8------------123----5---------9------114--------------10

大概就是这个重组模式，不要嫌弃描述太抽象，图片上传不上来，空格显示不出来，我也无奈

思路

分两个部分，一是最顶行和最底行，二是中间，分别对两个部分找规律了

代码

char* convert(char* s, int numRows) {char *a=(char*)malloc(sizeof(char)*(strlen(s)+1));int i,j,l,k=0,num=numRows*2-2;if(strlen(s)<=numRows || numRows==1){return s;}for(i=0;i<numRows;i++){if(i==0 || i==numRows-1){j=i;while(j<strlen(s)){a[k++]=s[j];j+=num;}}else{j=i;l=num-i;while(j<strlen(s) || l<strlen(s)){if(j<strlen(s)){a[k++]=s[j];j+=num;}if(l<strlen(s)){a[k++]=s[l];l+=num;}               }}}a[k]='\0';return a;
}

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