原文：

I am trying to validate that a php7 function accept only integers.

This is the class:

declare(strict_types=1);

class Post

{

private $id;

public function setId(int $id)

{

$this->id = $id;

}

}

And this is the test:

declare(strict_types=1);

class PostTest extends \PHPUnit_Framework_TestCase

{

private function getPostEntity()

{

return new Post();

}

public function testSetId()

{

$valuesExpected = [123, '123a'];

foreach ($valuesExpected as $input) {

$this->getPostEntity()->setId($input);

}

}

}

The error I get is:

TypeError: Argument 1 passed to Post::setId() must be of the type integer, string given, called in /path/test/PostTest.php on line 35

Is it possible to validate such error? also, does it make any sense to run such a check?

# Answer 1

Yes, you can test for TypeError the same way you would use for any other exception.

However, I would not test that PHP emits a type error in case of a type mismatch. This is the kind of test that becomes superfluous with PHP 7 code.

# Answer 2

Sadly, TypeError is not a subclass of Exception (reference), whilst it extends Error. The only thing they are really sharing is the the Throwable interface. The ThrowMatcher can't actually catch a TypeError.

If you look at the code in

src/PhpSpec/Matcher/ThrowMatcher.php,

you can see that PHPSpec catches Exceptions that inherit 'Exception'

and then checks the instance type of that exception.

# Answer 3

Try this:

$this->expectException(TypeError::class);

# Answer 4

For newer PHP versions try:

$this->expectError(TypeError::class);