tiktokOA fizz buzz

自己做的

class Solution {public:vector<string> fizzBuzz(int n) {vector<string> res;for(int i = 1; i <= n; i++){if(i % 3 == 0){if(i % 5 == 0){res.push_back("FizzBuzz");}else{res.push_back("Fizz");}}else if(i % 5 == 0)res.push_back("Buzz");else{string temp = to_string(i);res.push_back(temp);}}return res;}
};

如果再增加几个整除的数，把Fizzbuzz换成 %30 += Fizz， %50 += Buzz会更简洁

也可以用哈希表存对应的串
So, for FizzBuzzJazz the hash table would look something like { 3: ‘Fizz’, 5: ‘Buzz’, 7: ‘Jazz’ }

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