复数的四则运算（+，-，*，\）

此程序实现了对复数的加减乘除，输入的是实部和虚部。我分别用了c=a+b和a+=b;两个方法共同实现，代码如下，如果逻辑及代码有遗漏，欢迎随时评论，如果输入3，1则进行3+i和3+i的和为6+2i


public class Complex {//定义实部和虚部private double a;private double b;public Complex(){this(0.0,0.0);}public  Complex(double a){this(a,0.0);}public  Complex(double a,double b){this.a=a;this.b=b;}public  Complex(Complex c){this(c.a,c.b);}public double getA() {return a;}public void setA(double a) {this.a = a;}public double getB() {return b;}public void setB(double b) {this.b = b;}//a+=b;public Complex add(Complex one){this.a=this.a+one.a;this.b=this.b+one.b;return this;//或用这种方法返回return this.a+one.a}//c=a+b;public Complex add1(Complex one,Complex another){this.a=one.a+another.a;this.b=one.b+another.b;return this;}//a-=b;//先构造一个复数的相反数方法private Complex xiangfan(Complex one){return new Complex(-one.a, -one.b);}//直接进行调用public Complex jian(Complex one){return this.add(xiangfan(one));}//c=a-b;public Complex jian1(Complex one,Complex another){return this.add1(xiangfan(one),xiangfan(another));}//a*=b;public Complex cheng(Complex one){double c=0.0;double d=0.0;c=this.a*one.a-this.b*one.b;d=this.a*one.b+this.b*one.a;this.a=c;this.b=d;return this;}//c=a*b;public Complex cheng1(Complex one,Complex another){return new Complex(one).cheng(another);}// a /= b;
//      public static DIYcomplex mul(DIYcomplex one, DIYcomplex other) {
//          return new DIYcomplex(one).cheng(other);
//      }public Complex div(Complex c) {double mod = c.a * c.a - c.b * c.b;double mod1=0.0;double mod2=0.0;mod1=(this.a*c.a - this.b*c.b)/mod;mod2=(this.b*c.a - this.a*c.b)/mod;this.a=mod1;this.b=mod2;//对除数进行判断是否等于0  if(Math.abs(mod) < 1e-6) {return null;}  return this;}@Overridepublic String toString() {return "DIYcomplex [a=" + a + "+" + b + "i ]";}public static void main(String[] args) {Complex c1 = new Complex(3.0,1.0);//此刻输入的是一个复数的实部与虚部，产生一个对象就是一个复数System.out.println(c1);Complex c2 = new Complex(3.0,1.0);c2.add(c2); System.out.println(c2);Complex c3 = new Complex(3.0,1.0);c3.jian(c3);System.out.println(c3);Complex c4 = new Complex(3,1);c4.cheng(c4);System.out.println(c4); Complex c5 = new Complex(2.0,1.0);c5.div(c5);System.out.println(c5);}}

运行结果为

DIYcomplex [a=3.0+1.0i ]

DIYcomplex [a=6.0+2.0i ]
DIYcomplex [a=0.0+0.0i ]
DIYcomplex [a=8.0+6.0i ]
DIYcomplex [a=1.0+0.0i ]

最近又写了个复数的四则运算，此次采用了static静态方法，不仅使代码更加简洁，逻辑上更有了深的认识。而对于static的使用规则，我总结到只要是有一个新类出现就会使用它。代码如下：

public class Complex {private double real;private double virtual;public Complex() {}public Complex(double real) {this(real, 0.0);// 若只输入一个数就是虚部为0}public Complex(double real, double virtual) {this.real = real;this.virtual = virtual;}public Complex(Complex one) {this.real = one.real;this.virtual = one.virtual;}public double getReal() {return real;}public void setReal(double real) {this.real = real;}public double getVirtual() {return virtual;}public void setVirtual(double virtual) {this.virtual = virtual;}@Overridepublic String toString() {return "Complex [real=" + real + ", virtual=" + virtual + "]";}// a=a+b;public Complex add(Complex one) {this.real = one.real + this.real;this.virtual = one.virtual + this.virtual;return this;}public static Complex xiangfan(Complex one) {return new Complex(-one.real, -one.virtual);}// c=a+bpublic static Complex add1(Complex one, Complex other) {return new Complex(one).add(other);}// a=a-bpublic Complex jian(Complex one) {return this.add(xiangfan(one));}// c=a-bpublic static Complex jian1(Complex one, Complex other) {return new Complex(one).jian(other);}// a=a*bpublic Complex cheng(Complex one) {double c = 0.0;double d = 0.0;c = one.real * this.real - one.virtual * this.virtual;d = this.real * one.virtual + one.real * this.virtual;this.real = c;this.virtual = d;return this;}// c=a*bpublic static Complex cheng1(Complex one, Complex other) {return new Complex(one).cheng(other);}// 倒数public static Complex daoshu(Complex one) {double mod = one.real * one.real - one.virtual * one.virtual;if (Math.abs(mod) < 1e-6) {return null;}double tt = one.real / mod;double dd = one.virtual / mod;return new Complex(tt, -dd);}// c=a/bpublic static Complex div1(Complex one, Complex other) {return new Complex(one).cheng(daoshu(other));}// a=a/bpublic Complex div11(Complex c) {double mod = c.real * c.real - c.virtual * c.virtual;double mod1 = 0.0;double mod2 = 0.0;mod1 = (this.real * c.real - this.virtual * c.virtual) / mod;mod2 = (this.virtual * c.real - this.real * c.virtual) / mod;this.real = mod1;this.virtual = mod2;if (Math.abs(mod) < 1e-6) {return null;}return this;}
}

测试类

package com.mec.Complex.core;public class Text {public static void main(String[] args) {Complex complex=new Complex(3.0,1.0);   complex.add(complex);System.out.println(complex);Complex complex1=new Complex(3.0,1.0);complex1.jian(complex1);System.out.println(complex1);Complex complex2=new Complex(3.0,1.0);complex2.cheng(complex2);System.out.println(complex2);Complex complex3=new Complex(10,1);complex3.div11(complex3);System.out.println(complex3);}}

这是结果：

Complex [real=6.0, virtual=2.0]
Complex [real=0.0, virtual=0.0]
Complex [real=8.0, virtual=6.0]
Complex [real=1.0, virtual=0.0]

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