Codeforce Problem 427A. Police Recruits

题目链接： http://codeforces.com/problemset/problem/427/A

题目意思：

警察和小偷的故事：某城市要办大事儿，需要整治社会治安，但人手不够，需要雇佣零时工，应付突发情况，条件如下：

1、一次雇佣的人不超过10个（刚开始读成了总数不超过10个），超过10个就当10个人处理

2、一个零时工一生只能处理一个罪犯

3、如果没有零时工或者零时数少于犯罪的数量，则发生相应的犯罪数量。如 p 个警察 t 个罪犯，则发生 t - p 犯罪。

思路：将上面三个条件模拟出来即可：

/* ****
* @Codeforce Problem 427A. Police Recruits
* @ 2014.5.11
******/#include <stdio.h>
int main(){int i, t, n, C, P, ans;scanf("%d", &n);C = P = ans = 0;for(i = 0; i < n; ++i){scanf("%d", &t);if(t > 10){P += 10;}else if(t > 0){P += t;}else if(t < 0){if(P + t > 0)P += t;else{ans += -P - t;P = 0;}}}printf("%d\n", ans);return 0;
}

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