我正在运行启动到终端的linux(没有gui)。

我有一个ZyBo电路板，它有一个ArmV7处理器。我写了一个C程序来输出PMOD上的时钟和相应的数据序列。 PMOD的切换速度高达50MHz。但是，我的程序创建的时钟只有115 Hz的最大频率。我需要这个程序尽可能快地输出，因为PMOD I使用的能力是50MHz。

我使用以下代码行编译了我的程序：

gcc -ofast (c_program)。

#include

#include

#define ARRAYSIZE 511

//________________________________________

//macro for the SIGNAL PMOD

//________________________________________

//DATA

//ZYBO Use Pin JE1

#define INIT_SIGNAL system("echo 54 > /sys/class/gpio/export"); system("echo out > /sys/class/gpio/gpio54/direction");

#define SIGNAL_ON system("echo 1 > /sys/class/gpio/gpio54/value");

#define SIGNAL_OFF system("echo 0 > /sys/class/gpio/gpio54/value");

//________________________________________

//macro for the "CLOCK" PMOD

//________________________________________

//CLOCK

//ZYBO Use Pin JE4

#define INIT_MYCLOCK system("echo 57 > /sys/class/gpio/export"); system("echo out > /sys/class/gpio/gpio57/direction");

#define MYCLOCK_ON system("echo 1 > /sys/class/gpio/gpio57/value");

#define MYCLOCK_OFF system("echo 0 > /sys/class/gpio/gpio57/value");

int main(void){

int myarray[ARRAYSIZE] = {//hard coded array for signal data

1,0,0,1,0,1,0,0,1,0,1,0,0,1,0,1,0,0,1,0,1,0,0,1,0,0,1,0,1,0,0,1,1,0,0,1,1,0,1,0,0,0,0,0,1,0,0,1,1,1,0,0,1,1,1,0,1,1,1,1,0,0,1,0,0,0,1,0,1,0,0,1,1,1,0,0,1,0,1,0,1,0,0,1,0,1,1,0,1,0,1,1,0,0,1,1,1,1,0,0,1,0,1,0,0,1,1,1,1,1,1,0,0,1,0,0,1,1,0,1,0,0,0,0,1,0,0,0,1,1,0,0,1,0,1,1,1,0,0,0,1,0,0,0,1,0,1,0,0,0,1,0,0,1,0,1,1,1,1,0,1,1,0,1,0,0,1,0,0,0,1,0,1,0,0,1,0,0,0,1,0,0,0,1,0,1,0,1,0,1,0,1,1,0,0,0,0,0,0,0,0,1,0,1,1,0,1,1,1,1,1,0,0,1,1,1,0,0,1,1,0,1,1,0,1,1,1,0,0,1,1,1,1,1,0,0,1,0,1,0,1,0,1,1,0,1,0,0,0,1,1,1,0,1,0,1,0,1,0,1,0,1,0,1,0,0,1,0,0,0,0,1,1,1,0,1,1,1,1,0,1,1,0,1,0,1,0,1,0,0,1,0,1,1,1,0,1,1,1,0,0,1,1,1,0,1,0,0,1,0,1,1,1,1,1,0,1,1,1,1,1,1,1,0,1,1,0,0,1,0,1,1,0,1,0,1,1,1,0,0,0,0,0,1,0,0,0,1,0,1,1,1,1,1,1,1,0,0,0,0,0,1,1,0,1,1,1,1,1,1,1,1,0,1,1,0,1,0,0,0,1,1,1,1,1,1,1,1,1,1,0,1,1,1,1,0,1,1,1,0,1,0,1,1,1,0,0,0,1,0,1,0,1,0,0,1,1,0,0,1,1,0,1,0,0,1,0,0,1,0,1,1,1,1,1,1,0,1,1,0,1,0,1,1,1,1,1,1,0,0,1,1,0,1,1,0,0,1,1,0,1,1,0,1,0,1,0,1,0,1,0,0,1,1,1,0,1,1,0,0,0,0,1,1,0,1,1,0,1,1,1,1,1,1,1,0,1,0,1,1,0,0,0,0,0,0,0,0,0,0,0

};

INIT_SIGNAL

INIT_MYCLOCK;

//infinite loop

int i;

do{

i = 0;

do{

/*

1020 is chosen because it is twice the size needed allowing for the changes in the clock.

(511= 0-510, 510*2= 1020 ==> 0-1020 needed, so 1021 it is)

*/

if((i%2)==0)

{

MYCLOCK_ON;

if(myarray[i/2] == 1){

SIGNAL_ON;

}else{

SIGNAL_OFF;

}

}

else if((i%2)==1)

{

MYCLOCK_OFF;

//dont need to change the signal since it will just stay at whatever it was.

}

++i;

} while(i < 1021);

} while(1);

return 0;

}

如何使我的可执行程序输出至少达到MegaHertz的大小？