c语言给定一个非空整数数组

Problem statement: Write a C Program to check if all the bits of a given integer is one (1).

问题陈述：编写一个C程序来检查给定整数的所有位是否都是一(1) 。

Solution: We can use bitwise operator here to solve the problem.

解决方案：我们可以在这里使用按位运算符来解决问题。

Pre-requisite: Input number n

前提条件 ：输入数字n

Algorithm:

算法：

1)  Do Bitwise AND with n and 1.
n & 1
let n be a7a6a5a4a3a2a1a0
1->00000001
So doing bitwise AND (refer to published article on bitwise operators)
will result in all bits 0 except the LSB which will be a0.
If a0 is 0 then the all bits are not set
Thus,
IF
n & 1 ==0
Print that all bits are not same
ELSE
Right shift n by 1
n=n>>1
END IF-ELSE
2)  IF n==0
Print that all bits are set
ELSE
REPEAT step 1

Example with Explanation:

解释示例：

Checking for 12
12-> 00001100
So first iteration:
n=12 //00001100
n & 1 ==0
so print that all bits are not set
Checking for 7
7->00000111
So first iteration:
n=7 //00000111
n & 1 =1
n=n>>1 (n=3) //00000011
So second iteration:
n=3 //00000011
n & 1 =1
n=n>>1 (n=1) //00000001
So third iteration:
n=1 //00000001
n & 1 =1
n=n>>1 (n=0) //00000000
So, All bits are set

C implementation

C实现

#include <stdio.h>
int main()
{unsigned int n;
printf("enter the integer\n");
scanf("%d",&n);
while(n>0){int temp=n&1;
if(temp == 0){ //if any bit not set
printf("all bits are not set\n");
return 0;
}
n=n>>1; //right shift operator
}
printf("all bits are set ");
printf("in its binary representation\n");
return 0;
}

Output

输出量

First run:
enter the integer
12
all bits are not set
Second run:
enter the integer
7
all bits are set in its binary representation

翻译自: https://www.includehelp.com/c-programs/check-if-all-the-bits-of-a-given-integer-is-one-1.aspx

c语言给定一个非空整数数组