found character ‘@‘ that cannot start any token. (Do not use @ for indentation)
2024-07-02 17:18:54
控制台提示：
org.yaml.snakeyaml.scanner.ScannerException: while scanning for the next token
found character '@' that cannot start any token. (Do not use @ for indentation)in 'reader', line 4, column 15:password: @xxxxxxxxx^at org.yaml.snakeyaml.scanner.ScannerImpl.fetchMoreTokens(ScannerImpl.java:439)at org.yaml.snakeyaml.scanner.ScannerImpl.checkToken(ScannerImpl.java:248)at org.yaml.snakeyaml.parser.ParserImpl$ParseBlockMappingValue.produce(ParserImpl.java:665)at org.yaml.snakeyaml.parser.ParserImpl.peekEvent(ParserImpl.java:165)at org.yaml.snakeyaml.comments.CommentEventsCollector$1.peek(CommentEventsCollector.java:59)at org.yaml.snakeyaml.comments.CommentEventsCollector$1.peek(CommentEventsCollector.java:45)at org.yaml.snakeyaml.comments.CommentEventsCollector.collectEvents(CommentEventsCollector.java:140)at org.yaml.snakeyaml.comments.CommentEventsCollector.collectEvents(CommentEventsCollector.java:119)at org.yaml.snakeyaml.composer.Composer.composeScalarNode(Composer.java:214)at org.yaml.snakeyaml.composer.Composer.composeNode(Composer.java:184)at org.yaml.snakeyaml.composer.Composer.composeKeyNode(Composer.java:310)at org.yaml.snakeyaml.composer.Composer.composeMappingChildren(Composer.java:301)at org.yaml.snakeyaml.composer.Composer.composeMappingNode(Composer.java:286)at org.yaml.snakeyaml.composer.Composer.composeNode(Composer.java:188)at org.yaml.snakeyaml.composer.Composer.composeValueNode(Composer.java:314)at org.yaml.snakeyaml.composer.Composer.composeMappingChildren(Composer.java:305)at org.yaml.snakeyaml.composer.Composer.composeMappingNode(Composer.java:286)at org.yaml.snakeyaml.composer.Composer.composeNode(Composer.java:188)at org.yaml.snakeyaml.composer.Composer.composeValueNode(Composer.java:314)at org.yaml.snakeyaml.composer.Composer.composeMappingChildren(Composer.java:305)at org.yaml.snakeyaml.composer.Composer.composeMappingNode(Composer.java:286)at org.yaml.snakeyaml.composer.Composer.composeNode(Composer.java:188)at org.yaml.snakeyaml.composer.Composer.getNode(Composer.java:115)at org.yaml.snakeyaml.constructor.BaseConstructor.getData(BaseConstructor.java:135)at org.springframework.boot.env.OriginTrackedYamlLoader$OriginTrackingConstructor.getData(OriginTrackedYamlLoader.java:99)at org.yaml.snakeyaml.Yaml$1.next(Yaml.java:514)截图：
错误原因：
连接数据库的yml文件以@开头导致无法匹配启动。
解决方法：
用双引号将密码包括起来
spring:datasource:username: rootpassword: "@xxxxxx"driver-class-name: com.mysql.cj.jdbc.Driverurl: jdbc:mysql://120.22.22.222:3226/22found character ‘@‘ that cannot start any token. (Do not use @ for indentation)相关推荐
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