c++第八周【任务1-3】实现复数类中的运算符重载

/* (程序头部注释开始)
* 程序的版权和版本声明部分
* Copyright (c) 2011, 烟台大学计算机学院学生
* All rights reserved.
* 文件名称：
* 作    者： 李洪悬
* 完成日期：   2012      年   4    月   11     日
* 版 本 号：
* 对任务及求解方法的描述部分
* 输入描述：
* 问题描述：
* 程序输出：
* 程序头部的注释结束
*/

【任务1】实现复数类中的运算符重载
定义一个复数类重载运算符+、-、*、/，使之能用于复数的加减乘除。
（1）方案一：请用类的成员函数完成运算符的重载；
class Complex
{
public:
Complex(){real=0;imag=0;}
Complex(double r,double i){real=r;imag=i;}
Complex operator+(Complex &c2);
Complex operator-(Complex &c2);
Complex operator*(Complex &c2);
Complex operator/(Complex &c2);
void display();
private:
double real;
double imag;
};
//下面定义成员函数
int main()
{
Complex c1(3,4),c2(5,-10),c3;
cout<<"c1=";
c1.display();
cout<<"c2=";
c2.display();
c3=c1+c2;
cout<<"c1+c2=";
c3.display();
c3=c1-c2;
cout<<"c1-c2=";
c3.display();
c3=c1*c2;
cout<<"c1*c2=";
c3.display();
c3=c1/c2;
cout<<"c1/c2=";
c3.display();
system("pause");
return 0;
}
（2）方案二：请用类的友元函数，而不是成员函数，完成上面提及的运算符的重载；
（3）方案三：在方案二的基础上，扩展+、-、*、/运算符的功能，使之能与double型数据进行运算。设Complex c; double d; c?d和d?c的结果为将d视为实部为d的复数同c运算的结果（其中?为+、-、*、/之一）。另外，定义一目运算符-，-c相当于0-c。

#include < iostream >
using namespace std;
class Complex
{
public:
Complex()
{
real=0;
imag=0;
}
Complex (double r,double i)
{
real=r;
imag=i;
}
Complex operator - ();//求反函数
friend Complex operator + (Complex &c1 , Complex &c2);
friend Complex operator - (Complex &c1 , Complex &c2);
friend Complex operator * (Complex &c1 , Complex &c2);
friend Complex operator / (Complex &c1 , Complex &c2);
friend Complex operator + (double d , Complex &c1);
friend Complex operator - (double d , Complex &c1);
friend Complex operator * (double d , Complex &c1);
friend Complex operator /(double d , Complex &c1);
friend Complex operator + (Complex &c1, double d);
friend Complex operator - (Complex &c1, double d);
friend Complex operator * (Complex &c1, double d);
friend Complex operator / (Complex &c1, double d);
void display();
private:
double real;
double imag;
};
Complex Complex ::operator - ()
{
return Complex(0 - this->real,0 - this->imag);//  return (0 - *this);更好！
}
//复数相加:  (a+bi)+(c+di)=(a+c)+(b+d)i.
Complex operator + (Complex &c1 , Complex &c2)
{
Complex c;
c.real = c1.real + c2.real;
c.imag =c1.imag + c2.imag;
return c;
}
//复数相减:(a+bi)-(c+di)=(a-c)+(b-d)i.
Complex operator - (Complex &c1 , Complex &c2)
{
Complex c;
c.real = c1.real - c2.real;
c.imag = c1.imag - c2.imag;
return c;
}
//复数相乘:(a+bi)(c+di)=(ac－bd)+(bc+ad)i.
Complex operator * (Complex &c1 , Complex &c2)
{
Complex c;
c.real = c1.real * c2.real - c1.imag * c2.imag;
c.imag = c1.imag * c2.real + c1.real * c2.imag;
return c;
}
//复数相除:(a+bi)/(c+di)=(ac+bd)/(c^2+d^2) +(bc-ad)/(c^2+d^2)i
Complex operator / (Complex &c1 , Complex  &c2)
{
Complex c;
c.real = (c1.real * c2.real + c1.imag * c2.imag) / (c2.real * c2.real + c2.imag * c2.imag);
c.imag = (c1.imag * c2.real - c1.real * c2.imag) / (c2.real * c2.real + c2.imag * c2.imag);
return c;
}
//浮点型双精度数和复数相加
Complex operator + (double d , Complex &c1)
{
return Complex( d+c1.real , c1.imag);
}
//浮点型双精度数和复数相减
Complex operator - (double d , Complex &c1)
{
return Complex( d - c1.real , -c1.imag);
}
//浮点型双精度数和复数相乘
Complex operator * (double d , Complex &c1)
{
Complex c(d ,0);
return (c * c1);
}
//浮点型双精度数和复数相除
Complex operator / (double d , Complex &c1)
{
Complex c(d , 0);
return ( c / c1);
}
//浮点型双精度数和复数相加
Complex operator + ( Complex &c1, double d )
{
return Complex(c1.real + d , c1.imag);
}
//浮点型双精度数和复数相减
Complex operator - (Complex &c1, double d)
{
return Complex( c1.real - d , c1.imag);
}
//浮点型双精度数和复数相乘
Complex operator * (Complex &c1, double d)
{
Complex c(d ,0);
return (c1 * c);
}
//浮点型双精度数和复数相除
Complex operator / (Complex &c1, double d)
{
Complex c(d , 0);
return ( c1 / c);
}
void Complex::display()
{
cout << "(" << real << " , " << imag << "i)" << endl;
}
int main()
{
Complex c1(3 , 4),c2(5 , -10),c3;
double d = 7.5;
cout << " d = " << d << endl;
cout << " c1 = ";
c1.display();
cout << " c2 = ";
c2.display();
cout << "对C1和C2求反：" << endl;
cout << " - c1 = ";
c3 = - c1;
c3.display();
cout << " - c2 = ";
c3 = - c2;
c3.display();
c3 = c1 + c2;
cout << " c1 + c2 = ";
c3.display();
c3 = c1 - c2;
cout << " c1 - c2 = ";
c3.display();
c3 = c1 * c2;
cout << " c1 * c2 = ";
c3.display ();
c3 = c1 / c2;
cout << " c1 / c2 = ";
c3.display ();
c3 = d + c1;
cout << " d + c1 =";
c3.display();
c3 = d - c1;
cout << " d - c1 = ";
c3.display();
c3 = d * c1;
cout << " d * c1 = ";
c3.display ();
c3 = d / c1;
cout << " d / c1 = ";
c3.display ();
c3 =c1 + d ;
cout << " c1 + d = ";
c3.display();
c3 = c1 - d;
cout << " c1 - d =";
c3.display();
c3 = c1 * d;
cout << " c1 * d =";
c3.display ();
c3 = c1 / d;
cout << " c1 / d =";
c3.display ();
system ( " pause " );
return 0;
}

c++第八周【任务1-3】实现复数类中的运算符重载相关推荐

第十二周上机实践项目项目1-实现复数类中的运算符重载 (2)
问题及代码: [项目-实现复数类中的运算符重载] (1)请用类的成员函数,定义复数类重载运算符+.-.*./,使之能用于复数的加减乘除 class Complex { public:Complex() ...

c++第八周【任务1-3】实现复数类中的运算符重载

c++第八周【任务1-3】实现复数类中的运算符重载相关推荐

最新文章

热门文章