2022吴的机器学习C1-W2 Home Work：线性回归

2 - 问题描述

假设你是一家餐厅加盟店的首席执行官，正在考虑在不同的城市开设新的分店。

你想把业务扩展到可能给你的餐馆带来更高利润的城市。
该连锁店已经在不同的城市设有餐厅，你有这些城市的利润和人口数据。
你也有一些城市的数据，这些城市是新餐厅的候选城市。
- 对于这些城市，你有城市人口的数据。

你能利用这些数据来帮助你确定哪些城市有可能给你的企业带来更高的利润吗？

3 - 数据集

你将从加载这个任务的数据集开始。

下面显示的load_data()函数将数据加载到变量x_train和y_train中。
- x_train是一个城市的人口
- y_train是该城市的餐馆的利润。利润的负值表示亏损。
- X_train和y_train都是numpy数组。

import numpy as np
import matplotlib.pyplot as plt
from utils import *
import copy
import math# %matplotlib inline   →  plt.show()# load the dataset
x_train, y_train = load_data()
# print x_train
print("Type of x_train:", type(x_train))
print("First five elements of x_train are:\n", x_train[:5])
# print y_train
print("Type of y_train:", type(y_train))
print("First five elements of y_train are:\n", y_train[:5])
# 打印x_train和y_train的形状，看看你的数据集中有多少训练实例。
print('The shape of x_train is:', x_train.shape)
print('The shape of y_train is: ', y_train.shape)
print('Number of training examples (m):', len(x_train))# 创建一个数据的散点图。要将标记改为红色的 "x",
# 我们使用了'marker'和
# 'c'参数   c就是color
plt.scatter(x_train, y_train, marker='x', c='r')# 设置标题
plt.title("Profits vs. Population per city")
# 设置y轴标签
plt.ylabel('Profit in $10,000')
# 设置x轴标签
plt.xlabel('Population of City in 10,000s')
plt.show()def compute_cost(x, y, w, b):# number of training examplesm = x.shape[0]# You need to return this variable correctlytotal_cost = 0### START CODE HERE #### Variable to keep track of sum of cost from each examplecost_sum = 0# Loop over training examplesfor i in range(m):# Your code here to get the prediction f_wb for the ith examplef_wb = w * x[i] + b# Your code here to get the cost associated with the ith examplecost = (f_wb - y[i]) ** 2# Add to sum of cost for each examplecost_sum = cost_sum + cost# Get the total cost as the sum divided by (2*m)total_cost = (1 / (2 * m)) * cost_sum### END CODE HERE ###return total_cost# UNQ_C2# GRADED FUNCTION: compute_gradientdef compute_gradient(x, y, w, b):"""Computes the gradient for linear regressionArgs:x (ndarray): Shape (m,) Input to the model (Population of cities)y (ndarray): Shape (m,) Label (Actual profits for the cities)w, b (scalar): Parameters of the modelReturnsdj_dw (scalar): The gradient of the cost w.r.t. the parameters wdj_db (scalar): The gradient of the cost w.r.t. the parameter b"""# Number of training examplesm = x.shape[0]# You need to return the following variables correctlydj_dw = 0dj_db = 0### START CODE HERE ###for i in range(m):f_wb = w * x[i] + bdj_db_i = f_wb - y[i]dj_dw_i = (f_wb - y[i]) * x[i]# Update dj_db : In Python, a += 1  is the same as a = a + 1dj_db += dj_db_i# Update dj_dwdj_dw += dj_dw_i# Divide both dj_dw and dj_db by mdj_dw = dj_dw / mdj_db = dj_db / m
#    dj_db = (w * x + b - y).sum() / m
#    dj_dw = ((w * x + b - y) * x).sum() / m### END CODE HERE ###return dj_dw, dj_dbdef gradient_descent(x, y, w_in, b_in, cost_function, gradient_function, alpha, num_iters):"""Performs batch gradient descent to learn theta. Updates theta by takingnum_iters gradient steps with learning rate alphaArgs:x :    (ndarray): Shape (m,)y :    (ndarray): Shape (m,)w_in, b_in : (scalar) Initial values of parameters of the modelcost_function: function to compute costgradient_function: function to compute the gradientalpha : (float) Learning ratenum_iters : (int) number of iterations to run gradient descentReturnsw : (ndarray): Shape (1,) Updated values of parameters of the model afterrunning gradient descentb : (scalar)                Updated value of parameter of the model afterrunning gradient descent"""# number of training examplesm = len(x)# An array to store cost J and w's at each iteration — primarily for graphing laterJ_history = []w_history = []w = copy.deepcopy(w_in)  # avoid modifying global w within functionb = b_infor i in range(num_iters):# Calculate the gradient and update the parametersdj_dw, dj_db = gradient_function(x, y, w, b)# Update Parameters using w, b, alpha and gradientw = w - alpha * dj_dwb = b - alpha * dj_db# Save cost J at each iterationif i < 100000:  # prevent resource exhaustioncost = cost_function(x, y, w, b)J_history.append(cost)# Print cost every at intervals 10 times or as many iterations if < 10if i % math.ceil(num_iters / 10) == 0:w_history.append(w)print(f"Iteration {i:4}: Cost {float(J_history[-1]):8.2f}   ")return w, b, J_history, w_history  # return w and J,w history for graphing# initialize fitting parameters. Recall that the shape of w is (n,)
initial_w = 0.
initial_b = 0.# some gradient descent settings
iterations = 1500
alpha = 0.01w,b,_,_ = gradient_descent(x_train ,y_train, initial_w, initial_b,compute_cost, compute_gradient, alpha, iterations)
print("w,b found by gradient descent:", w, b)m = x_train.shape[0]
predicted = np.zeros(m)for i in range(m):predicted[i] = w * x_train[i] + b# Plot the linear fit
plt.plot(x_train, predicted, c = "b")# Create a scatter plot of the data.
plt.scatter(x_train, y_train, marker='x', c='r')# Set the title
plt.title("Profits vs. Population per city")
# Set the y-axis label
plt.ylabel('Profit in $10,000')
# Set the x-axis label
plt.xlabel('Population of City in 10,000s')
plt.show()

题目翻译原文：

王者归来，全新升级！吴恩达《机器学习2022》——民间自制中文翻译版 - 知乎

引用和数据文件：

https://download.csdn.net/download/qq_27785023/86737600

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2022吴的机器学习C1-W2 Home Work：线性回归

2 - 问题描述

3 - 数据集

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