kotlin 查找id

A transpose of a matrix is simply a flipped version of the original matrix.
We can transpose a matrix by switching its rows with its columns

矩阵的转置只是原始矩阵的翻转形式。
我们可以通过切换矩阵的行和列来转置矩阵

Given a matrix, we have to find its transpose matrix.

给定一个矩阵，我们必须找到它的转置矩阵。

Example:

例：

    Input:
matrix:
[2, 3, 4, 5, 6]
[7, 8, 9, 0, 9]
Output:
Transpose Matrix :
[2, 7]
[3, 8]
[4, 9]
[5, 0]
[6, 9]

在Kotlin中寻找矩阵转置的程序 (Program to find transpose of a matrix in Kotlin)

package com.includehelp
import java.util.*
// Main function, Entry Point of Program
fun main(args: Array<String>) {
//variable of rows and col
val rows: Int
val column: Int
//Input Stream
val scanner = Scanner(System.`in`)
//Input no of rows and column
print("Enter the number of rows and columns of matrix : ")
rows   = scanner.nextInt()
column = scanner.nextInt()
//Create Array
val matrixA     = Array(rows) { IntArray(column) }
val transposeMatrix = Array(column) {IntArray(rows)}
//Input Matrix
println("Enter the Elements of First Matrix ($rows X $column} ): ")
for(i in matrixA.indices){
for(j in matrixA[i].indices){
print("matrixA[$i][$j]: ")
matrixA[i][j]=scanner.nextInt()
}
}
//print Matrix A
println("Matrix A : ")
for(i in matrixA.indices){
println("${matrixA[i].contentToString()} ")
}
//Transpose of Matrix
for(i in transposeMatrix.indices){
for(j in transposeMatrix[i].indices){
transposeMatrix[i][j]=matrixA[j][i]
}
}
//print Transpose Matrix
println("Transpose Matrix : ")
for(i in transposeMatrix.indices){
println("${transposeMatrix[i].contentToString()} ")
}
}

Output

输出量

Run 1:
Enter the number of rows and columns of matrix : 3
4
Enter the Elements of First Matrix (3 X 4} ):
matrixA[0][0]: 2
matrixA[0][1]: 3
matrixA[0][2]: 4
matrixA[0][3]: 5
matrixA[1][0]: 6
matrixA[1][1]: 7
matrixA[1][2]: 8
matrixA[1][3]: 9
matrixA[2][0]: 0
matrixA[2][1]: 1
matrixA[2][2]: 2
matrixA[2][3]: 3
Matrix A :
[2, 3, 4, 5]
[6, 7, 8, 9]
[0, 1, 2, 3]
Transpose Matrix :
[2, 6, 0]
[3, 7, 1]
[4, 8, 2]
[5, 9, 3]
----
Run 2:
Enter the number of rows and columns of matrix : 2
5
Enter the Elements of First Matrix (2 X 5} ):
matrixA[0][0]: 2
matrixA[0][1]: 3
matrixA[0][2]: 4
matrixA[0][3]: 5
matrixA[0][4]: 6
matrixA[1][0]: 7
matrixA[1][1]: 8
matrixA[1][2]: 9
matrixA[1][3]: 0
matrixA[1][4]: 9
Matrix A :
[2, 3, 4, 5, 6]
[7, 8, 9, 0, 9]
Transpose Matrix :
[2, 7]
[3, 8]
[4, 9]
[5, 0]
[6, 9]

翻译自: https://www.includehelp.com/kotlin/find-transpose-of-a-matrix.aspx

kotlin 查找id