1.输入监听emoji，然后拦截掉

/**

* 将系统表情转化为字符串

*

* @param s

* @return

*/

public static boolean havaEmoji(String s) {

int length = s.length();

String context = "";

//循环遍历字符串，将字符串拆分为一个一个字符

for (int i = 0; i < length; i++) {

char codePoint = s.charAt(i);

//判断字符是否是emoji表情的字符

if (isEmojiCharacter(codePoint)) {

//如果是就返回

return true;

}

}

return false;

}

//使用

mBinding.etContent.addTextChangedListener(new TextWatcher() {

@Override

public void beforeTextChanged(CharSequence charSequence, int i, int i1, int i2) {

}

@Override

public void onTextChanged(CharSequence charSequence, int i, int i1, int i2) {

}

@Override

public void afterTextChanged(Editable editable) {

int index = mBinding.etContent.getSelectionStart();//获取光标位置

if (havaEmoji(editable.toString())) {//包含表情就删掉这个表情

editable.delete(index - 1, index);//删除光标前的字符

return;

}

}

});

2.不拦截掉emoji，直接约定转换，前端转成String，后台接受时转成emoji

//前台转换

/**

* 将系统表情转化为字符串

*

* @param s

* @return

*/

public static String getString(String s) {

int length = s.length();

String context = "";

//循环遍历字符串，将字符串拆分为一个一个字符

for (int i = 0; i < length; i++) {

char codePoint = s.charAt(i);

//判断字符是否是emoji表情的字符

if (isEmojiCharacter(codePoint)) {

//如果是将以大括号括起来

String emoji = "{" + Integer.toHexString(codePoint) + "}";

context = context + emoji;

continue;

}

context = context + codePoint;

}

return context;

}

/**

* 是否包含表情

*

* @param codePoint

* @return 如果不包含 返回false,包含 则返回true

*/

public static boolean isEmojiCharacter(char codePoint) {

return !((codePoint == 0x0) || (codePoint == 0x9) || (codePoint == 0xA)

|| (codePoint == 0xD)

|| ((codePoint >= 0x20) && (codePoint <= 0xD7FF))

|| ((codePoint >= 0xE000) && (codePoint <= 0xFFFD)) || ((codePoint >= 0x10000) && (codePoint <= 0x10FFFF)));

}

//后台转换

/**

* 将表情描述转换成表情

*

* @param str

* @return

*/

public static String getEmoji(Context context, String str) {

String string = str;

String rep = "\\{(.*?)\\}";

Pattern p = Pattern.compile(rep);

Matcher m = p.matcher(string);

while (m.find()) {

String s1 = m.group().toString();

String s2 = s1.substring(1, s1.length() - 1);

String s3;

try {

s3 = String.valueOf((char) Integer.parseInt(s2, 16));

string = string.replace(s1, s3);

} catch (Exception e) {

e.printStackTrace();

}

}

return string;

}

标签：codePoint,return,String,处理,int,context,android,emoji,Emoji

来源： https://blog.csdn.net/qq_27381325/article/details/88116799