oracle树结构查询语句

今天修改了个功能，修改车辆分类树。现在将其前后端记录下来，主要代码如下：

1、js代码：

1.1 js获取数据

var UITree = function () {var vehTypeTree = function() {$("#div_treeId").jstree({"core" : {"themes" : {"responsive": false}, // so that create works"check_callback" : true,'data' : function (obj, callback) {$.ajax({type : "POST",async : true,url : "后端地址?parentId=#",  //#为根节点的iddata : "",dataType : "JSON",success : function(data) {callback.call(this, data);},error:function(err){err;}});}},"types" : {"default" : {"icon" : "fa fa-folder icon-state-warning icon-lg"},"file" : {"icon" : "fa fa-file icon-state-warning icon-lg"}},"plugins" : [ "dnd", "types", "checkbox", "wholerow" ]});}return {//main function to initiate the moduleinit: function () {//车辆类别选择vehTypeTree();}};}();

1.2 页面加载

$(function() {if (App.isAngularJsApp() === false) {jQuery(document).ready(function() {UITree.init();$('#div_treeId').on("ready.jstree",function(e, data) {loadAllReportData();});});}});

div什么的就不贴了，稍微随便写一点就OK。

2、controller代码和工具类：

@RequestMapping(value = "/后台地址", method = RequestMethod.POST)public void test(@RequestParam String parentId) {try {//result里面存树结构的链表List<Map<String, Object>> result = service.qry_CLFL(parentId);test2(result);} catch (Exception e) {e.printStackTrace();}}
//工具类writeJson方法
protected void test2(Object jsonObj) {PrintWriter out = null;try {response.setContentType("text/html");out = response.getWriter();String jsonStr = null;if (jsonObj instanceof String) { //对比数据类型jsonStr = jsonObj.toString();} else {jsonStr = JsonUtils.toJson(jsonObj);}out.write(jsonStr);out.flush();out.close();} catch (Exception e) {e.printStackTrace();}}
//工具类构造我们需要的树结构方法
public static List<Map<String, Object>> test1(List<Map<String, Object>> resultList) {if (resultList != null && resultList.size() > 0) {List<Map<String, Object>> retList = new ArrayList<Map<String, Object>>();Map<String, Object> m = new HashMap<String, Object>();for (Map<String, Object> map : resultList) {m.put("需要的字段", map.get("需要的字段"));m.put("需要的字段", map.get("需要的字段"));m.put("需要的字段", map.get("需要的字段"));Map<String, Object> s = new HashMap<String, Object>();if (map.get("默认选中字段")!=null && map.get("默认选中字段").toString().equals("1") ){s.put("selected", true);s.put("opened", true);}m.put("state", s);    retList.add(m);m = new HashMap<String, Object>();                }return retList;}return null;}

3、service代码

 @Overridepublic List<Map<String, Object>> qry_CLFL(String parentId) throws Exception {// TODO Auto-generated method stubStringBuffer strBuf = new StringBuffer("");strBuf.append(" sql代码 ");      List<Map<String, Object>> resultList = jdbcTemplate.queryForList(strBuf.toString());if (resultList != null && resultList.size() > 0)return ListUtil.convertListForJsTreeByT_B_VEHICLE_TAG(resultList);//调工具类return null;}

4、sql

 select "需要的字段"F_GetCntOfT_B_VEHICLE(t.id) as vehcnt,  --通过t.id查找此ID的数量level as lev,CONNECT_BY_ISLEAF as isleaf --CONNECT_BY_ISLEAF 为判断是否是最底节点from tableA tstart with t.pid = '#' --#为根节点connect by prior t.id = t.pid --pid为父类节点id  t.id为tpid的子节点order siblings by t.orderno   --以t.orderno进行分支排序--创建函数
create or replace function F_GetCntOfT_B_VEHICLE(传入的ID in varchar2) return number iscnt number;
beginselect count(0)into cntfrom tableB vwhere v.分类ID in (select idfrom tableA tstart with t.id = "传入的ID"connect by prior t.id = t.pid);return(cnt);
end;

本人学识浅薄，有总结的不到位或是不准确的地方，欢迎指正。

=================================补充分割线==============================

两棵树：

通过sql语句查询到树分类的list，由于是两棵树，根节点为 '#' 的数据应该有两个条。

组装树：

@RequestMapping("/getVehicleTree")
public void getVehicleTree(HttpServletRequest request, HttpServletResponse response) throws IOException {List<Map<String, Object>> list = vehicleService.selectAllVehicleTag();TreeNode root1 = null;TreeNode root2 = null;int flag = 1;for (int i = 0; i< list.size(); i++) {Map<String, Object> map = list.get(i);if (map.get("PID").toString().equals("#")) {if (flag == 1) {//找到第一棵树父节点root1 = new TreeNode(map.get("ID").toString(), map.get("PID").toString(), map.get("TAGNAME").toString());flag ++;//2}else {flag ++;//3//找到第二棵树父节点root2 = new TreeNode(map.get("ID").toString(), map.get("PID").toString(), map.get("TAGNAME").toString());}} else {TreeNode cNode = new TreeNode(map.get("ID").toString(), map.get("PID").toString(),map.get("TAGNAME").toString());if(flag == 2){root1.add(cNode);}else {root2.add(cNode);}}}String str3 ="["+ JSONArray.toJSONString(root1) +","+ JSONArray.toJSONString(root2)+"]";response.setCharacterEncoding("utf-8");response.setContentType("text");response.getWriter().println(str3);response.flushBuffer();}

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