cf1191 A. Tokitsukaze and Enhancement

Tokitsukaze is one of the characters in the game “Kantai Collection”. In this game, every character has a common attribute — health points, shortened to HP.

In general, different values of HP are grouped into 4 categories:

Category A if HP is in the form of (4n+1), that is, when divided by 4, the remainder is 1;
Category B if HP is in the form of (4n+3), that is, when divided by 4, the remainder is 3;
Category C if HP is in the form of (4n+2), that is, when divided by 4, the remainder is 2;
Category D if HP is in the form of 4n, that is, when divided by 4, the remainder is 0.
The above-mentioned n can be any integer.

These 4 categories ordered from highest to lowest as A>B>C>D, which means category A is the highest and category D is the lowest.

While playing the game, players can increase the HP of the character. Now, Tokitsukaze wants you to increase her HP by at most 2 (that is, either by 0, 1 or 2). How much should she increase her HP so that it has the highest possible category?

Input
The only line contains a single integer x (30≤x≤100) — the value Tokitsukaze’s HP currently.

Output
Print an integer a (0≤a≤2) and an uppercase letter b (b∈{A,B,C,D}), representing that the best way is to increase her HP by a, and then the category becomes b.

Note that the output characters are case-sensitive.

Examples
33
0 A

98
1 B
Note
For the first example, the category of Tokitsukaze’s HP is already A, so you don’t need to enhance her ability.

For the second example:

If you don’t increase her HP, its value is still 98, which equals to (4×24+2), and its category is C.
If you increase her HP by 1, its value becomes 99, which equals to (4×24+3), and its category becomes B.
If you increase her HP by 2, its value becomes 100, which equals to (4×25), and its category becomes D.
Therefore, the best way is to increase her HP by 1 so that the category of her HP becomes B.
**题意：**把数字对4取模或分别对应一个字母值，字母等级关系为A>B>C>D,分别对应的取模后数字为1,3,2,0;现在输入一个数字，可将数字加0或1或2，输出能对应的最高字母等级。
**分析：**如果数字对4取模后为1，直接输出0 A，如果数字对4取模后为2，直接输出1 B，如果数字对4取模后为3，直接输出2 A，如果数字对4取模后为0，直接输出1 A。

#include <iostream>
#include <algorithm>
using namespace std;
int main() {int n;cin >> n;if (n % 4 == 1) {printf("0 A\n");} else if (n % 4 == 3) {printf("2 A\n");} else if (n % 4 == 2) {printf("1 B\n");} else {printf("1 A\n");}return 0;
}

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