mysql-Codeigniter-多个数据库连接

我必须从主数据库中检索MySQL数据库信息，然后连接到该数据库，并获取一些记录。

我的意思是持有一个数据库，我想加载另一个数据库。

Codeigniter是否可能？ 现在，我在模型中使用以下代码行。

function connectDb($credential)

{

$config['hostname'] = $credential['server'];

$config['username'] = $credential['username'];

$config['password'] = $credential['password'];

$config['database'] = $credential['database'];

$config['dbdriver'] = "mysql";

$config['dbprefix'] = "";

$config['pconnect'] = FALSE;

$config['db_debug'] = TRUE;

$config['cache_on'] = FALSE;

$config['cachedir'] = "";

$config['char_set'] = "utf8";

$config['dbcollat'] = "utf8_general_ci";

$DB2=$this->load->database($config);

$DB2->db->select('first_name,last_name');

$query = $DB2->db->get('person');

print_r($query);

}

它不起作用还有其他办法吗？

6个解决方案

80 votes

您应该在“ application / config / database.php”中提供第二个数据库信息

通常，您将设置$db['default']数据库组，如下所示：

$db['default']['hostname'] = "localhost";

$db['default']['username'] = "root";

$db['default']['password'] = "";

$db['default']['database'] = "database_name";

$db['default']['dbdriver'] = "mysql";

$db['default']['dbprefix'] = "";

$db['default']['pconnect'] = TRUE;

$db['default']['db_debug'] = FALSE;

$db['default']['cache_on'] = FALSE;

$db['default']['cachedir'] = "";

$db['default']['char_set'] = "utf8";

$db['default']['dbcollat'] = "utf8_general_ci";

$db['default']['swap_pre'] = "";

$db['default']['autoinit'] = TRUE;

$db['default']['stricton'] = FALSE;

请注意，登录信息和设置在名为$db['default']的数组中提供。

然后，您可以在新数组中添加另一个数据库-我们称其为“ otherdb”。

$db['otherdb']['hostname'] = "localhost";

$db['otherdb']['username'] = "root";

$db['otherdb']['password'] = "";

$db['otherdb']['database'] = "other_database_name";

$db['otherdb']['dbdriver'] = "mysql";

$db['otherdb']['dbprefix'] = "";

$db['otherdb']['pconnect'] = TRUE;

$db['otherdb']['db_debug'] = FALSE;

$db['otherdb']['cache_on'] = FALSE;

$db['otherdb']['cachedir'] = "";

$db['otherdb']['char_set'] = "utf8";

$db['otherdb']['dbcollat'] = "utf8_general_ci";

$db['otherdb']['swap_pre'] = "";

$db['otherdb']['autoinit'] = TRUE;

$db['otherdb']['stricton'] = FALSE;

如何实际使用第二个数据库，您必须将连接发送到可以在模型中使用的另一个变量：

function my_model_method()

{

$otherdb = $this->load->database('otherdb', TRUE); // the TRUE paramater tells CI that you'd like to return the database object.

$query = $otherdb->select('first_name, last_name')->get('person');

var_dump($query);

}

那应该做。可在以下位置找到用于连接多个数据库的文档：[http://codeigniter.com/user_guide/database/connecting.html]

Repox answered 2020-02-04T00:15:38Z

18 votes

最好的方法是使用不同的数据库组。 如果要继续照常使用主数据库($ this-> db)，只需关闭辅助数据库的持久连接配置选项即可。 只有master数据库应该与持久连接一起工作：

主数据库

$db['default']['hostname'] = "localhost";

$db['default']['username'] = "root";

$db['default']['password'] = "";

$db['default']['database'] = "database_name";

$db['default']['dbdriver'] = "mysql";

$db['default']['dbprefix'] = "";

$db['default']['pconnect'] = TRUE;

$db['default']['db_debug'] = FALSE;

$db['default']['cache_on'] = FALSE;

$db['default']['cachedir'] = "";

$db['default']['char_set'] = "utf8";

$db['default']['dbcollat'] = "utf8_general_ci";

$db['default']['swap_pre'] = "";

$db['default']['autoinit'] = TRUE;

$db['default']['stricton'] = FALSE;

辅助数据库(注意pconnect设置为false)

$db['otherdb']['hostname'] = "localhost";

$db['otherdb']['username'] = "root";

$db['otherdb']['password'] = "";

$db['otherdb']['database'] = "other_database_name";

$db['otherdb']['dbdriver'] = "mysql";

$db['otherdb']['dbprefix'] = "";

$db['otherdb']['pconnect'] = FALSE;

$db['otherdb']['db_debug'] = FALSE;

$db['otherdb']['cache_on'] = FALSE;

$db['otherdb']['cachedir'] = "";

$db['otherdb']['char_set'] = "utf8";

$db['otherdb']['dbcollat'] = "utf8_general_ci";

$db['otherdb']['swap_pre'] = "";

$db['otherdb']['autoinit'] = TRUE;

$db['otherdb']['stricton'] = FALSE;

然后，您可以照常使用主数据库，而将辅助数据库用作数据库对象：

// use master dataabse

$users = $this->db->get('users');

// connect to secondary database

$otherdb = $this->load->database('otherdb', TRUE);

$stuff = $otherdb->get('struff');

$otherdb->insert_batch('users', $users->result_array());

// keep using master database as usual, for example insert stuff from other database

$this->db->insert_batch('stuff', $stuff->result_array());

Simmoniz answered 2020-02-04T00:16:11Z

14 votes

用这个。

$dsn1 = 'mysql://user:password@localhost/db1';

$this->db1 = $this->load->database($dsn1, true);

$dsn2 = 'mysql://user:password@localhost/db2';

$this->db2= $this->load->database($dsn2, true);

$dsn3 = 'mysql://user:password@localhost/db3';

$this->db3= $this->load->database($dsn3, true);

用法

$this->db1 ->insert('tablename', $insert_array);

$this->db2->insert('tablename', $insert_array);

$this->db3->insert('tablename', $insert_array);

Rayiez answered 2020-02-04T00:16:36Z

11 votes

这对我来说可以...

这是默认数据库：

$db['default'] = array(

'dsn' => '',

'hostname' => 'localhost',

'username' => 'root',

'password' => '',

'database' => 'mydatabase',

'dbdriver' => 'mysqli',

'dbprefix' => '',

'pconnect' => TRUE,

'db_debug' => (ENVIRONMENT !== 'production'),

'cache_on' => FALSE,

'cachedir' => '',

'char_set' => 'utf8',

'dbcollat' => 'utf8_general_ci',

'swap_pre' => '',

'encrypt' => FALSE,

'compress' => FALSE,

'stricton' => FALSE,

'failover' => array(),

'save_queries' => TRUE

);

在database.php文件的底部添加另一个数据库

$db['second'] = array(

'dsn' => '',

'hostname' => 'localhost',

'username' => 'root',

'password' => '',

'database' => 'mysecond',

'dbdriver' => 'mysqli',

'dbprefix' => '',

'pconnect' => TRUE,

'db_debug' => (ENVIRONMENT !== 'production'),

'cache_on' => FALSE,

'cachedir' => '',

'char_set' => 'utf8',

'dbcollat' => 'utf8_general_ci',

'swap_pre' => '',

'encrypt' => FALSE,

'compress' => FALSE,

'stricton' => FALSE,

'failover' => array(),

'save_queries' => TRUE

);

在autoload.php配置文件中

$autoload['libraries'] = array('database', 'email', 'session');

通过自动加载数据库库，默认数据库可以正常工作   但是第二个数据库通过在模型中使用构造函数来加载和连接   控制器...

class Seconddb_model extends CI_Model {

function __construct(){

parent::__construct();

//load our second db and put in $db2

$this->db2 = $this->load->database('second', TRUE);

}

public function getsecondUsers(){

$query = $this->db2->get('members');

return $query->result();

}

}

?>

Mani answered 2020-02-04T00:17:13Z

6 votes

在查看代码时，我唯一看到的错误是，当您尝试加载第二个数据库时：

$DB2=$this->load->database($config);

当您要检索数据库对象时，必须在第二个参数中传递TRUE。

从Codeigniter用户指南中：

通过将第二个参数设置为TRUE(布尔值)，该函数将   返回数据库对象。

因此，您的代码应改为：

$DB2=$this->load->database($config, TRUE);

这将使其工作。

Quetzy Garcia answered 2020-02-04T00:17:55Z

0 votes

If you need to connect to more than one database simultaneously you can do so as follows:

$DB1 = $this->load->database('group_one', TRUE);

$DB2 = $this->load->database('group_two', TRUE);

注意：将单词“ group_one”和“ group_two”更改为您要连接的特定组名(或者您可以如上所示传递连接值)。

通过将第二个参数设置为TRUE(布尔值)，该函数将返回数据库对象。

请访问[https://www.codeigniter.com/userguide3/database/connecting.html]以获取更多信息。

Dhiraj Shrestha answered 2020-02-04T00:18:24Z