#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char s2[12][50]={{"-----"},{".----"},{"..---"},{"...--"},{"....-"},{"....."},{"-...."},{"--..."},{"---.."},{"----."}};
char s80[12][50]={{"-----"},{"-- ---."},{"-- ---.."},{"-- ---..."},{"-- ---...."},{"-- ---....."},{"-...."},{"--..."},{"---.."},{"----."}};
void pr (long long int n,int i)
{char str[1000][100]={0};int h=0;int j;if (i==2){while (n/10>0)//这里先判断他有没有10位。//这样，就避免了他是0的情况{strcpy(str[h++],s2[n%10]);n /= 10;}strcpy(str[h],s2[n]);//加上最后一位for (j=h;j>=0;j--){printf ("%s",str[j]);}printf ("\n");}else{while (n/10>0){strcpy(str[h++],s80[n%10]);n /= 10;}strcpy(str[h],s80[n]);for (j=h;j>=0;j--){printf ("%s",str[j]);}printf ("\n");}return ;
}
void work()
{int m;scanf ("%d",&m);char str1[100]={0};char str2[100]={0};getchar();//接收上面M的那个回车//就是scanf("%d",&m)的回车gets(str1);gets(str2);//gets 有吃回车的功能/*printf ("%s\n",str1);printf ("%s\n",str2);*/int i;int len1 = strlen(str1);int len2 = strlen(str2);char str_next[100]={0};//用来判断下一个//用于判断80那里的。有重复的嫌疑char str_temp[100]={0};int h=0;int j;int f=0;int flag;long long int number1=0;long long int number2=0;//long long int sum = number1+number2;if (m==2){for (i=0;i<len1;i++){str_temp[h++] = str1[i];//一个一个字符处理，力求取最大的flag=0;for (j=0;j<10;j++){str_temp[h]='\0';if (strcmp(str_temp,s2[j])==0){if (i!=len1-1){strcpy(str_next,str_temp);str_next[h]=str1[i+1];str_next[h+1]='\0';for (f=0;f<10;f++){if (strcmp(str_next,s2[f])==0)//如果再取多一个字符，它是存在的//那么就选最长得那个{flag=1;break;}}}else flag = 0;if (!flag){number1 = number1*10+j;h=0;memset(str_temp,0,sizeof(str_temp));memset(str_next,0,sizeof(str_next));}}}}h=0;flag=0;memset(str_temp,0,sizeof(str_temp));memset(str_next,0,sizeof (str_next));for (i=0;i<len2;i++){str_temp[h++] = str2[i];flag=0;//记得是设置为0//刚开始就是一个没设置为0//一直WA//0代表他再取一个字符，//str_next 不存在于s2中for (j=0;j<10;j++){str_temp[h]='\0';if (strcmp(str_temp,s2[j])==0){if (i!=len2-1){strcpy(str_next,str_temp);str_next[h]=str2[i+1];str_next[h+1]='\0';for (f=0;f<10;f++){if (strcmp(str_next,s2[f])==0){flag=1;break;}}}else flag=0;if (!flag){number2 = number2*10+j;h=0;memset(str_temp,0,sizeof(str_temp));memset(str_next,0,sizeof(str_next));}}}}pr(number1+number2,2);}else{h=0;flag=0;for (i=0;i<len1;i++){str_temp[h++] = str1[i];flag=0;for (j=0;j<10;j++){str_temp[h]='\0';if (strcmp(str_temp,s80[j])==0){if (i!=len1-1){strcpy(str_next,str_temp);str_next[h]=str1[i+1];str_next[h+1]='\0';for (f=0;f<10;f++){if (strcmp(str_next,s80[f])==0){flag=1;break;}}}else flag=0;if (!flag){number1 = number1*10+j;h=0;memset(str_temp,0,sizeof(str_temp));memset(str_next,0,sizeof(str_next));}}}}h=0;memset(str_temp,0,sizeof(str_temp));memset(str_next,0,sizeof(str_next));for (i=0;i<len2;i++){str_temp[h++] = str2[i];flag=0;for (j=0;j<10;j++){str_temp[h]='\0';if (strcmp(str_temp,s80[j])==0){if (i!=len2-1){strcpy(str_next,str_temp);str_next[h]=str2[i+1];str_next[h+1]='\0';for (f=0;f<10;f++){if (strcmp(str_next,s80[f])==0){flag=1;break;}}}else flag=0;if (!flag){number2 = number2*10+j;memset(str_temp,0,sizeof(str_temp));memset(str_next,0,sizeof(str_next));h=0;}}}}pr(number1+number2,80);}return ;
}
int main()
{int t;scanf ("%d",&t);while (t--){work();}return 0;
}