NSN的MGM SW engineer面试题

1. 给出标准的MIN的宏定义

2. int a = 100;

char* str = (char*)malloc(sizeof(100));

问：

变量a 是放在栈中还是堆中。

字符串str指向的分配空间是放在栈中还是堆中。

3. int ucData[100];

for(int i=0; i<100; ++i)

{

ucData[i] = i;

}

char cOut = *(char*)( (int)ucData + 1 );

cOut的值是多少？

4. 用C语言定义一个包含10个元素的数组；每一个元素都是一个有整数的参数并返回整数的函数

5. 下面的程序能否运行？如果不能，怎么改正？

void GetMemory(char* p)

{

p = (char*)malloc(sizeof(100));

}

int main(void)

{

char* str = NULL;

GetMemory(str);

strcpy(str, "hello world!");

printf("%s", str);

}

6.给出下面函数的输出：

int function1(const char* s, const char* access)

{

char* p = NULL;

char* a = NULL;

int count = 0;

for(p = s; *p != '/0'; ++p)

{

for(a = access; *a != '/0'; ++a)

if(*a == *p) break;

if *a == '/0' return count

else

++count

}

// 该函数的目的是找出s中连续的几个在access中的字符的长度

// 比如s为-=def, access为“=-”，返回2

char* function2(const char* s, const char* access)

{

while(*s != '/0')

{

char* a = access; // 这段代码记得不是很真切

while(*a != '/0')

{

if(*a++ == *s++) return s;

}

++s;

}

return NULL;

}

char* function3

// --- function1,function2, function3 几个函数就是从字符串中分出由分隔符隔离开的taken

// 具体的代码，请让我想想再写。

void main(void)

{

char s[] = "-abc-=def=g"

char* str1 = NULL;

str1 = functions3(s, "-");

printf("str1=%s/n", str1);

str1 = functions3(NULL, "-=");

printf("str1=%s/n", str1);

str1 = functions3(s, "=");

printf("str1=%s/n", str1);

printf("s=%s/n", s);

}

7. 给链表按照递增的顺序排序。

struct Node{

int data;

Node* next;

}

要求不允许用临时性的数组（还有一个要求，记不清楚了，不过不影响题目）。

函数的声明如下：

Node* increase_sort_list(Node* pheader);

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