Lightoj_1422

题目：

求最小要多少件衣服

思路

初始化dp[i][i] = 1;

枚举长度{枚举开头{if(a[j] == a[L] 继承dp[j][L - 1]); dp[j][L]取min forever}}；

ACcode

#include<cstdio>
#include<iostream>
#include<algorithm>
#include<cstring>
#include<cmath>using namespace std;
const int inf = 0x3f3f3f3f;int t,n;
int dp[105][105],a[105];int main()
{scanf("%d",&t);for(int T = 1;T <= t; T++){scanf("%d",&n);for(int i = 1;i <= n; i++) scanf("%d",&a[i]);for(int i = 1;i <= n; i++){for(int j = 1;j <= n; j++){dp[i][j] = inf;if(i == j) dp[i][j] = 1;}}for(int i = 2;i <= n; i++){//枚举长度for(int j = 1;j + i - 1 <= n; j++){//枚举开头int L = j + i - 1;if(a[j] == a[L]) dp[j][L] = dp[j][L - 1];for(int f = j;f < L; f++){dp[j][L] = min(dp[j][L],dp[j][f] + dp[f + 1][L]);}}}printf("Case %d: %d\n",T,dp[1][n]);}
}

Lightoj_1422

题目：

思路

ACcode

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