Codeforces 892 A.Greed

A. Greed

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

Jafar has n cans of cola. Each can is described by two integers: remaining volume of cola ai and can's capacity bi (ai ≤ bi).

Jafar has decided to pour all remaining cola into just 2 cans, determine if he can do this or not!

Input

The first line of the input contains one integer n (2 ≤ n ≤ 100 000) — number of cola cans.

The second line contains n space-separated integers a1, a2, ..., an (0 ≤ ai ≤ 109) — volume of remaining cola in cans.

The third line contains n space-separated integers that b1, b2, ..., bn (ai ≤ bi ≤ 109) — capacities of the cans.

Output

Print "YES" (without quotes) if it is possible to pour all remaining cola in 2 cans. Otherwise print "NO" (without quotes).

You can print each letter in any case (upper or lower).

Examples

input

23 53 6

output

YES

input

36 8 96 10 12

output

NO

input

50 0 5 0 01 1 8 10 5

output

YES

input

44 1 0 35 2 2 3

output

YES

Note

In the first sample, there are already 2 cans, so the answer is "YES".

分析：签到题，排个序看容量最大的杯子能否装下.

#include <cstdio>
#include <cmath>
#include <queue>
#include <cstring>
#include <iostream>
#include <algorithm>using namespace std;long long n, a[100010], b[100010], sum;int main()
{cin >> n;for (int i = 1; i <= n; i++){long long t;cin >> t;sum += t;}for (int i = 1; i <= n; i++)cin >> b[i];sort(b + 1, b + 1 + n);if (sum <= b[n] + b[n - 1])puts("YES");elseputs("NO");return 0;
}

转载于:https://www.cnblogs.com/zbtrs/p/7858282.html

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