题目

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example,
Given s = "Hello World",
return 5.

代码

public class Solution {public int lengthOfLastWord(String s) {if(s.length()==0) return 0;char[] chars=s.toCharArray();char empty=' ';int lengthOfLastWord=0;int lengthOfLastWord_temp=0;for(int i=0;i<s.length();i++){if(chars[i]!=empty){lengthOfLastWord++;lengthOfLastWord_temp=lengthOfLastWord;}else {lengthOfLastWord=0;}}if(chars[s.length()-1]==empty) return lengthOfLastWord_temp;else  return lengthOfLastWord;}
}

代码下载：https://github.com/jimenbian/GarvinLeetCode

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【LeetCode从零单排】No58.Length of Last Word

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