1 #include <iostream>
 2 #include <cstdio>
 3 #include <cstdlib>
 4 #include <algorithm>
 5 using namespace std;
 6
 7 static char dd[2][13] = {
 8     {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31},
 9     {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}
10 };
11
12 int jd_year(int year)
13 {
14     if (year % 4 == 0 && year % 100 != 0 || year % 400 == 0)
15         return 1;
16     return 0;
17 }
18
19 int day_of_year(int year, int month, int day)  // 算出该日期在该year年处于第几天
20 {
21     for (int i = 1; i < month; i++)
22         day += dd[jd_year(year)][i];
23     return day;
24 }
25
26 int main()
27 {
28     int y, m, d, y1, m1, d1, i, cnt;
29     scanf("%d:%d:%d", &y, &m, &d);
30     scanf("%d:%d:%d", &y1, &m1, &d1);
31     if (y > y1 || (y == y1 && m > m1) || (y == y1 && m == m1 && d > d1))
32     {
33         swap(y, y1);
34         swap(m, m1);
35         swap(d, d1);
36     }
37     if (y == y1)
38     {
39         if (m != m1)
40         {
41             cnt = dd[jd_year(y)][m]-d + d1;
42             for (i = m+1; i < m1; i++)
43                 cnt += dd[jd_year(y)][i];
44         }
45         else
46             cnt = d1 - d;
47     }
48     else
49     {
50         cnt = day_of_year(y, m, d);
51         if (jd_year(y))
52             cnt = 366 - cnt;
53         else
54             cnt = 365 - cnt;
55         cnt += day_of_year(y1, m1, d1);
56         for (i = y+1; i < y1; i++)
57         {
58             if (jd_year(i))
59                 cnt += 366;
60             else
61                 cnt += 365;
62         }
63     }
64     printf("%d\n", cnt);
65     return 0;
66 }
67
68