Leetcode 2327. Number of People Aware of a Secret [Python]

BFS版本会TLE，最后还是要DP。两个版本都写写吧。
BFS的话，while循环的控制是天数，而不是len(que).

class Solution:def peopleAwareOfSecret(self, n: int, delay: int, forget: int) -> int:Mod = 10**9 + 7container = collections.deque()container.append((delay, forget))Day = 1while Day != n:size = len(container)for _ in range(size):nodedelay, nodelife = container.popleft()if nodedelay > 1 and nodelife != 0 :container.append((nodedelay-1, nodelife-1))elif (nodedelay == 0 or nodedelay -1 == 0) and nodelife - 1 != 0:container.append((0, nodelife-1))container.append((delay, forget))Day += 1return len(container)%Mod

好了，DP版本。

class Solution:def peopleAwareOfSecret(self, n: int, delay: int, forget: int) -> int:dp = [0 for _ in range(1000)]dp[0] = 1for i in range(delay, n):if i < forget - 1:dp[i] = sum(dp[:i-delay+1])else:dp[i] = sum(dp[i-forget + 1:i-delay+1])return sum(dp[n-forget:])%(10**9+7)

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