lab3

页表初始化过程:

物理页是一组由run结构体保存的,每个runmain函数调用kinit,初始化物理页。kinit调用了freerange。把内核对应的物理页全部释放掉,加入到freelist(由run组成的链表)中。(因为内核的虚拟地址和物理地址是直接映射的,所以就是end到PHYSTOP)freerange又调用了kfree(void *p)函数,这个函数的作用就是释放p这一页,从p开始,pgsize大小的空间全被置为1,然后把p转换为*run类型,用头插法把*p加入到freelist中,也是就*p的值是原先freelist的地址。这样从end到PHYSTOP对应的物理页就全被初始化,并被保存到freelist中去了。然后main又调用kvminit。kvminit首先通过kalloc创建内核的root page-table page 。然后调用kvmmap install the translations that the kernel needs(不知道这句话咋翻译)。kvmmap实际是调用mappages实现这个功能。
int
mappages(pagetable_t pagetable, uint64 va, uint64 size, uint64 pa, int perm)
{uint64 a, last;pte_t *pte;a = PGROUNDDOWN(va);last = PGROUNDDOWN(va + size - 1);for(;;){if((pte = walk(pagetable, a, 1)) == 0)return -1;if(*pte & PTE_V)panic("remap");*pte = PA2PTE(pa) | perm | PTE_V;//printf("%p   %p   \n",pa,PA2PTE(pa));if(a == last)break;a += PGSIZE;pa += PGSIZE;}return 0;
}
是创建一个页表项,映射虚拟地址va开始的size个字节到物理地址pa。walk返回的是最后一级页表的页表项地址。然后将walk返回的这项改为物理地址pa。

然后main调用kvminithart,让系统能够映射。把kernel pagetable存入寄存器。
然后main调用procinit,为每个进程分配kernel stack。

一些点

在内核部分,虚拟地址和物理地址是直接映射的,虚拟地址和物理地址的区别就是多了10个标志位。

Print a page table

这个实验比较简单,参照freewalk的代码就好了。

void
vmp(pagetable_t pagetable, int depth){if(depth>2) return;    for(int i=0; i<512;i++){pte_t pte = pagetable[i];if((pte & PTE_V)){for(int j=0;j<depth;j++){printf(".. ");}    uint64 child = PTE2PA(pte);printf("..%d: pte %p pa %p\n",i,pte,child);  vmp((pagetable_t)child,depth+1);}}
}
void
vmprint(pagetable_t pagetable){printf("page table %p\n",pagetable);vmp(pagetable,0);
}

A kernel page table per process

  这个实验和下个实验要做的是使内核能直接解析用户指针。利用的是内核在虚拟地址较高的部分开始,而进程从0开始。这个实验要做的就是为每个进程创建一个kernel pagetable,然后在运行这个进程的时候,把系统的kernel pagetable切换为进程的kernel pagetable。这个实验做的时候挺难的,现在写起复盘好像还好。
struct proc {struct spinlock lock;// p->lock must be held when using these:enum procstate state;        // Process statestruct proc *parent;         // Parent processvoid *chan;                  // If non-zero, sleeping on chanint killed;                  // If non-zero, have been killedint xstate;                  // Exit status to be returned to parent's waitint pid;                     // Process ID// these are private to the process, so p->lock need not be held.uint64 kstack;               // Virtual address of kernel stackuint64 sz;                   // Size of process memory (bytes)pagetable_t pagetable;       // User page tablepagetable_t kernel_pagetable; //user kernel pagetablestruct trapframe *trapframe; // data page for trampoline.Sstruct context context;      // swtch() here to run processstruct file *ofile[NOFILE];  // Open filesstruct inode *cwd;           // Current directorychar name[16];               // Process name (debugging)
};
根据提示,首先要做的是往proc 结构体加个 kernel pagetable。
pagetable_t
proc_kernel_pagetable(){pagetable_t kpagetable = (pagetable_t)kalloc();memset(kpagetable, 0 ,PGSIZE);mappages(kpagetable, UART0, PGSIZE, UART0,PTE_R |PTE_W); mappages(kpagetable,VIRTIO0, PGSIZE, VIRTIO0, PTE_R | PTE_W);//mappages(kpagetable, CLINT, 0x10000, CLINT, PTE_R | PTE_W);mappages(kpagetable, PLIC, 0x400000, PLIC, PTE_R | PTE_W);mappages(kpagetable, KERNBASE, (uint64)etext-KERNBASE, KERNBASE, PTE_R | PTE_X );mappages(kpagetable,(uint64)etext, PHYSTOP-(uint64)etext, (uint64)etext, PTE_R | PTE_W);mappages(kpagetable,TRAMPOLINE, PGSIZE, (uint64)trampoline, PTE_R | PTE_X);return kpagetable;
}
然后参照kvminit,写一个初始化进程的kernel pagetable的函数。 注释掉的那行是因为在第三个实验不需要映射。要注意的是注意mappages里面的标志位参数,有两个是PTE_X,全是读写的话,会卡在一个地方,进不了shell。
static struct proc*
allocproc(void)
{struct proc *p;for(p = proc; p < &proc[NPROC]; p++) {acquire(&p->lock);if(p->state == UNUSED) {goto found;} else {release(&p->lock);}}return 0;found:p->pid = allocpid();//lab 3 初始化p->kernel_pagetable=proc_kernel_pagetable();//kstackchar *pa = kalloc();if(pa==0)panic("stack kalloc");uint64 va = (TRAMPOLINE - 2*PGSIZE);mappages(p->kernel_pagetable, va, PGSIZE,(uint64)pa, PTE_R | PTE_W);p->kstack = va; // Allocate a trapframe page.if((p->trapframe = (struct trapframe *)kalloc()) == 0){release(&p->lock);return 0;}// An empty user page table.p->pagetable = proc_pagetable(p);if(p->pagetable == 0){freeproc(p);release(&p->lock);return 0;}// Set up new context to start executing at forkret,// which returns to user space.memset(&p->context, 0, sizeof(p->context));p->context.ra = (uint64)forkret;p->context.sp = p->kstack + PGSIZE;return p;
}
接下来就是改allocproc函数,主要有两个:1.初始化进程的kernel pagetable2.修改kernel stack。因为每个进程的kernel stack是映射在kernel pagetable的,所以这里需要把procinit的部分功能移到这来。
void
scheduler(void)
{struct proc *p;struct cpu *c = mycpu();c->proc = 0;for(;;){// Avoid deadlock by ensuring that devices can interrupt.intr_on();int found = 0;for(p = proc; p < &proc[NPROC]; p++) {acquire(&p->lock);if(p->state == RUNNABLE) {// Switch to chosen process.  It is the process's job// to release its lock and then reacquire it// before jumping back to us.p->state = RUNNING;c->proc = p;w_satp(MAKE_SATP(p->kernel_pagetable));sfence_vma();swtch(&c->context, &p->context);kvminithart();// Process is done running for now.// It should have changed its p->state before coming back.c->proc = 0;found = 1;}release(&p->lock);}
#if !defined (LAB_FS)if(found == 0) {intr_on();asm volatile("wfi");}
#else;
#endif}
}

修改scheduler,在进程调度的时候切换kernel pagetable。

void
free_kernel_pagetable(pagetable_t pagetable, uint64 stack,uint64 sz){uvmunmap(pagetable, UART0, 1, 0); uvmunmap(pagetable, VIRTIO0, 1, 0);  //uvmunmap(pagetable, CLINT, 0x10000/PGSIZE, 0);  uvmunmap(pagetable, PLIC, 0x400000/PGSIZE, 0);  uvmunmap(pagetable, KERNBASE, ((uint64)etext-KERNBASE)/PGSIZE, 0);  uvmunmap(pagetable, TRAMPOLINE, 1, 0);  uvmunmap(pagetable, (uint64)etext,(PHYSTOP-(uint64)etext)/PGSIZE , 0);  uvmunmap(pagetable, 0, PGROUNDUP(sz)/PGSIZE, 0);uvmunmap(pagetable, stack, 1, 1);freewalk(pagetable);
}
static void
freeproc(struct proc *p)
{if(p->trapframe)kfree((void*)p->trapframe);p->trapframe = 0;if(p->pagetable)proc_freepagetable(p->pagetable, p->sz);if(p->kernel_pagetable)free_kernel_pagetable(p->kernel_pagetable,p->kstack,p->sz);p->pagetable = 0;p->sz = 0;p->pid = 0;p->parent = 0;p->name[0] = 0;p->chan = 0;p->killed = 0;p->xstate = 0;p->state = UNUSED;
}// Create a user page table for a given process,
// with no user memory, but with trampoline pages.
pagetable_t
proc_pagetable(struct proc *p)
{pagetable_t pagetable;// An empty page table.pagetable = uvmcreate();if(pagetable == 0)return 0;// map the trampoline code (for system call return)// at the highest user virtual address.// only the supervisor uses it, on the way// to/from user space, so not PTE_U.if(mappages(pagetable, TRAMPOLINE, PGSIZE,(uint64)trampoline, PTE_R | PTE_X) < 0){uvmfree(pagetable, 0);return 0;}// map the trapframe just below TRAMPOLINE, for trampoline.S.if(mappages(pagetable, TRAPFRAME, PGSIZE,(uint64)(p->trapframe), PTE_R | PTE_W) < 0){uvmunmap(pagetable, TRAMPOLINE, 1, 0);uvmfree(pagetable, 0);return 0;}return pagetable;
}
然后就是释放进程的时候也要free 进程的kernel pagetable。因为这里贴的代码是做完了lab3的代码,所以有些内容和下个实验有关系。

Simplify copyin/copyinstr

 这个部分就是在之前实验的基础上,把进程的pagetable映射添加到kernel pagetable上,要注意PTE_U只能在用户态使用。
void
userinit(void)
{struct proc *p;pte_t *pte,*kernelpte;p = allocproc();initproc = p;// allocate one user page and copy init's instructions// and data into it.uvminit(p->pagetable, initcode, sizeof(initcode));p->sz = PGSIZE;//lab3pte= walk(p->pagetable,0,0);kernelpte = walk(p->kernel_pagetable,0,1);*kernelpte = (*pte) & (~PTE_U);// prepare for the very first "return" from kernel to user.p->trapframe->epc = 0;      // user program counterp->trapframe->sp = PGSIZE;  // user stack pointersafestrcpy(p->name, "initcode", sizeof(p->name));p->cwd = namei("/");p->state = RUNNABLE;release(&p->lock);
}
首先修改userinit。
int
fork(void)
{int i, pid;struct proc *np;struct proc *p = myproc();pte_t *pte,*kernelpte;// Allocate process.if((np = allocproc()) == 0){return -1;}// Copy user memory from parent to child.if(uvmcopy(p->pagetable, np->pagetable, p->sz) < 0){freeproc(np);release(&np->lock);return -1;}np->sz = p->sz;np->parent = p;//lab3 paet3for(int j=0;j< p->sz; j+=PGSIZE){kernelpte = walk(np->kernel_pagetable,j,1);pte = walk(np->pagetable,j,0);*kernelpte = (*pte) & (~PTE_U);}// copy saved user registers.*(np->trapframe) = *(p->trapframe);// Cause fork to return 0 in the child.np->trapframe->a0 = 0;// increment reference counts on open file descriptors.for(i = 0; i < NOFILE; i++)if(p->ofile[i])np->ofile[i] = filedup(p->ofile[i]);np->cwd = idup(p->cwd);safestrcpy(np->name, p->name, sizeof(p->name));pid = np->pid;np->state = RUNNABLE;release(&np->lock);return pid;
}
int
exec(char *path, char **argv)
{char *s, *last;int i, off;uint64 argc, sz = 0, sp, ustack[MAXARG+1], stackbase;struct elfhdr elf;struct inode *ip;struct proghdr ph;pagetable_t pagetable = 0, oldpagetable;struct proc *p = myproc();begin_op();if((ip = namei(path)) == 0){end_op();return -1;}ilock(ip);// Check ELF headerif(readi(ip, 0, (uint64)&elf, 0, sizeof(elf)) != sizeof(elf))goto bad;if(elf.magic != ELF_MAGIC)goto bad;if((pagetable = proc_pagetable(p)) == 0)goto bad;// Load program into memory.for(i=0, off=elf.phoff; i<elf.phnum; i++, off+=sizeof(ph)){if(readi(ip, 0, (uint64)&ph, off, sizeof(ph)) != sizeof(ph))goto bad;if(ph.type != ELF_PROG_LOAD)continue;if(ph.memsz < ph.filesz)goto bad;if(ph.vaddr + ph.memsz < ph.vaddr)goto bad;uint64 sz1;if((sz1 = uvmalloc(pagetable, sz, ph.vaddr + ph.memsz)) == 0)goto bad;if(sz1>=PLIC)goto bad;sz = sz1;if(ph.vaddr % PGSIZE != 0)goto bad;if(loadseg(pagetable, ph.vaddr, ip, ph.off, ph.filesz) < 0)goto bad;}iunlockput(ip);end_op();ip = 0;p = myproc();uint64 oldsz = p->sz;// Allocate two pages at the next page boundary.// Use the second as the user stack.sz = PGROUNDUP(sz);uint64 sz1;if((sz1 = uvmalloc(pagetable, sz, sz + 2*PGSIZE)) == 0)goto bad;sz = sz1;uvmclear(pagetable, sz-2*PGSIZE);sp = sz;stackbase = sp - PGSIZE;//lab3 part3// Push argument strings, prepare rest of stack in ustack.for(argc = 0; argv[argc]; argc++) {if(argc >= MAXARG)goto bad;sp -= strlen(argv[argc]) + 1;sp -= sp % 16; // riscv sp must be 16-byte alignedif(sp < stackbase)goto bad;if(copyout(pagetable, sp, argv[argc], strlen(argv[argc]) + 1) < 0)goto bad;ustack[argc] = sp;}ustack[argc] = 0;// push the array of argv[] pointers.sp -= (argc+1) * sizeof(uint64);sp -= sp % 16;if(sp < stackbase)goto bad;if(copyout(pagetable, sp, (char *)ustack, (argc+1)*sizeof(uint64)) < 0)goto bad;pte_t *pte, *kernel_pte;uvmunmap(p->kernel_pagetable,0,PGROUNDUP(oldsz)/PGSIZE,0);for(int j=0;j<sz;j+=PGSIZE){pte = walk(pagetable, j,0);kernel_pte = walk(p->kernel_pagetable, j, 1);*kernel_pte = ((*pte) & (~PTE_U));}// arguments to user main(argc, argv)// argc is returned via the system call return// value, which goes in a0.p->trapframe->a1 = sp;// Save program name for debugging.for(last=s=path; *s; s++)if(*s == '/')last = s+1;safestrcpy(p->name, last, sizeof(p->name));// Commit to the user image.oldpagetable = p->pagetable;p->pagetable = pagetable;p->sz = sz;p->trapframe->epc = elf.entry;  // initial program counter = mainp->trapframe->sp = sp; // initial stack pointerproc_freepagetable(oldpagetable, oldsz);if(p->pid==1)vmprint(p->pagetable); return argc; // this ends up in a0, the first argument to main(argc, argv)bad:if(pagetable)proc_freepagetable(pagetable, sz);if(ip){iunlockput(ip);end_op();}return -1;
}
 然后是fork和exec,这两个函数要做的操作本质是一样的。
uint64
sys_sbrk(void)
{int addr;int n;pte_t *pte,*kernel_pte;struct proc *p = myproc();if(argint(0, &n) < 0)return -1;addr = p->sz;if(growproc(n) < 0)return -1;if(n>0){for(int j=addr;j<addr+n;j+=PGSIZE){pte=walk(p->pagetable,j,0);kernel_pte = walk(p->kernel_pagetable,j,1);*kernel_pte = (*pte) & ~PTE_U; }}else{//for(int j=addr-PGSIZE;j>=addr+n;j-=PGSIZE) //     uvmunmap(p->kernel_pagetable,j,1,0 );uvmunmap(p->kernel_pagetable,PGROUNDUP(addr+n),-n/PGSIZE,0);}return addr;
}
 然后修改 sbrk,n是正数增加映射,负数减少映射。
int
copyin(pagetable_t pagetable, char *dst, uint64 srcva, uint64 len)
{/*uint64 n, va0, pa0;while(len > 0){va0 = PGROUNDDOWN(srcva);pa0 = walkaddr(pagetable, va0);if(pa0 == 0)return -1;n = PGSIZE - (srcva - va0);if(n > len)n = len;memmove(dst, (void *)(pa0 + (srcva - va0)), n);copyin_new(pagetable, dst, srcva, n);len -= n;dst += n;srcva = va0 + PGSIZE;}return 0;*/return copyin_new(pagetable, dst, srcva, len);
}
 最后就是修改copyin()和copyinstr()。这里我没太搞懂的是为什么可以直接return copyin_new(pagetable, dst, srcva, len); 不需要每一个PGSIZE调用一次这个函数,像注释掉的memmove(dst, (void *)(pa0 + (srcva - va0)), n);一样。 是因为之前因为内核不能直接识别用户指针,所以每一个PGSIZE就需要翻译一遍吗?

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