{"list1": [{"id": "238","username": "凤20","peiouid": "255,258"}],"list2": [{"id": "255","username": "wo1","peiouid": null},{"id": "258","username": "1231132","peiouid": ""}]
}

上面的两个list集合，我想通过条件查找list2中的id 是在  "peiouid": "255,258"的，找到后把他和在一起，
最终变成

方法如下

public class TestJson {public static void main(String[] args) {String s = "{" + "\"list1\": [" + "{" + "\"id\": \"238\","+ "\"username\": \"凤20\"," + "\"peiouid\": \"255,258\"" + "}"+ "]," + "\"list2\": [" + "{" + "\"id\": \"255\","+ "\"username\": \"wo1\"," + "\"peiouid\": null" + "}," + "{"+ "\"id\": \"258\"," + "\"username\": \"1231132\","+ "\"peiouid\": \"\"" + "}" + "]" + "}";JSONObject jo = JSON.parseObject(s);JSONArray joList1 = jo.getJSONArray("list1");String peiouid = joList1.getJSONObject(0).getString("peiouid");JSONArray jaList = new JSONArray();JSONArray jaList2 = jo.getJSONArray("list2");for(int i=0;i<jaList2.size();i++){JSONObject ji = jaList2.getJSONObject(i);if(peiouid.contains(ji.getString("id"))){jaList.add(ji);}}joList1.getJSONObject(0).put("list2", jaList);JSONObject jsonObject = new JSONObject();jsonObject.put("list1", joList1);System.out.println(jsonObject);}
}

         String s1 = "{\"list1\":" + JSONValue.toJSONString(mr_AddressList9)+ ",\"list2\":" + JSONValue.toJSONString(mr_AddressList10)+"}";JSONObject jo1 = JSON.parseObject(s1);JSONArray joList11 = jo1.getJSONArray("list1");for(int i=0;i<joList11.size();i++){  //针对行数据的时候String peiouid1 = joList11.getJSONObject(i).getString("peiouid");JSONArray jaList1 = new JSONArray();JSONArray jaList21 = jo1.getJSONArray("list2");for(int i1=0;i1<jaList21.size();i1++){JSONObject ji = jaList21.getJSONObject(i1);System.out.println("第555555555代人的老婆id>>>>>>>>>>"+peiouid1+">>>>>>>>>>第5555555代人的母亲的id>>>>>>>>>"+ji.getString("id"));if(peiouid1.contains(ji.getString("id"))){jaList1.add(ji);}}joList11.getJSONObject(i).put("list10", jaList1);  //put("list10"+i, jaList1) 这个变量 就名称不一样} jsonObjec1.put("list10", joList11);System.out.println(jsonObjec1);jsonObjec88=jsonObjec1;